QED Logic quod erat demonstrandum

A Medium 10×10 Puzzle Solved with Shape Squeeze in 19 Steps

10×10 · medium · 19 steps

Play this board yourself →
A
B
C
D
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H
I
J
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10×
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This 10×10 board rates as medium (difficulty score 840). Solving it from scratch takes 19 logical steps, using 6 techniques: Single cell, Row/column exclusion, Adjacency clear, Region confinement, Paired regions, Shape squeeze. Every step below is forced: nothing here is a guess.

  1. First, every open cell left in this region sits in column E, so its marker has to land there; that clears every other open cell in the column.
  2. Next, together, two regions have open cells only in rows 1 and 2; with one marker each, those two markers have to fill exactly those two rows, so every other region's open cells there can be cleared.
  3. Then, every open cell left in this region sits in row 3, so its marker has to land there; that clears every other open cell in the row.
  4. After that, every open cell left in this region sits in row 4, so its marker has to land there; that clears every other open cell in the row.
  5. Now, place a marker at H5. Region has exactly one open cell left. Placing here clears the rest of row 5, column H, and its region. Placing here also clears its 2 touching neighbours.
  6. From there, place a marker at J6. Region has exactly one open cell left. Placing here clears the rest of row 6, column J, and its region. Placing here also clears its 1 touching neighbour.
  7. Following that, place a marker at B7. Region has exactly one open cell left. Placing here clears the rest of row 7, column B, and its region. Placing here also clears its 2 touching neighbours.
  8. First, place a marker at A4. Region has exactly one open cell left. Placing here clears the rest of row 4, column A, and its region.
  9. Next, every remaining candidate in this region touches G2, so whichever candidate ends up marked will clear it, and it can be ruled out now regardless of which one wins.
  10. Then, every open cell left in this region sits in column I, so its marker has to land there; that clears every other open cell in the column.
  11. After that, together, two regions have open cells only in columns F and G; with one marker each, those two markers have to fill exactly those two columns, so every other region's open cells there can be cleared.
  12. Now, every open cell left in this region sits in row 10, so its marker has to land there; that clears every other open cell in the row.
  13. From there, every remaining candidate in this region touches C9 and D9, so whichever candidate ends up marked will clear them, and they can be ruled out now regardless of which one wins.
  14. Following that, place a marker at D8. Region has exactly one open cell left. Placing here clears the rest of row 8, column D, and its region.
  15. First, place a marker at G9. Region has exactly one open cell left. Placing here clears the rest of row 9, column G, and its region.
  16. Next, place a marker at F3. Region has exactly one open cell left. Placing here also clears its 1 touching neighbour.
  17. Then, place a marker at E1. Region has exactly one open cell left. Placing here clears the rest of row 1, column E, and its region.
  18. After that, place a marker at I2. Region has exactly one open cell left.
  19. Finally, place a marker at C10. Region has exactly one open cell left.

The key move here was Shape squeeze. Once you can spot that, this board falls quickly.